Include 'use_api' permission in the api.acl module

api/acl.py

@@ -24,7 +24,29 @@
 Here are defined some functions to check acl on the application.
 """
 
+
 from django.conf import settings
+from django.contrib.contenttypes.models import ContentType
+from django.contrib.auth.models import Permission
+
+
+# Creates the 'use_api' permission if not created
+# The 'use_api' is a fake permission in the sense
+# it is not associated with an existing model and
+# this ensure the permission is created every tun
+api_content_type, created = ContentType.objects.get_or_create(
+    app_label=settings.API_CONTENT_TYPE_APP_LABEL,
+    model=settings.API_CONTENT_TYPE_MODEL
+)
+if created:
+    api_content_type.save()
+api_permission, created = Permission.objects.get_or_create(
+    name=settings.API_PERMISSION_NAME,
+    content_type=api_content_type,
+    codename=settings.API_PERMISSION_CODENAME
+)
+if created:
+    api_permission.save()
 
 
 def can_view(user):

api/initial_perm.py

@@ -1,17 +0,0 @@
-from django.contrib.contenttypes.models import ContentType
-from django.contrib.auth.models import Permission
-from django.conf import settings
-
-api_content_type, created = ContentType.objects.get_or_create(
-    app_label=settings.API_CONTENT_TYPE_APP_LABEL,
-    model=settings.API_CONTENT_TYPE_MODEL
-)
-if created:
-    api_content_type.save()
-api_permission, created = Permission.objects.get_or_create(
-    name=settings.API_PERMISSION_NAME,
-    content_type=api_content_type,
-    codename=settings.API_PERMISSION_CODENAME
-)
-if created:
-    api_permission.save()

api/urls.py

@@ -28,7 +28,6 @@ from django.conf.urls import url, include
 from rest_framework.routers import DefaultRouter
 
 from . import views
-from . import initial_perm
 
 router = DefaultRouter()
 router.register(r'users', views.UserViewSet)